Math question....?

A Hive of Bees:


In a certain bee hive, one fifth of the bees flew to a rosebush one third to some honeysuckle;


three times the difference of these numbers alighted on goldenrod, and one flew about a daisy.


How many bees were in the hive?

Math question....?
Let the total number bees be X.





Rosebush - X/5


Honeysuckle - X/3


Golden Rod - 3*(X/3-X/5)= 2X/5


Daisy - 1





X/5+X/3+2X/5+1 = X


=%26gt; 15+14X = 15X


=%26gt; X = 15





Answer: 15 bees in all
Reply:There were 15 bees. Difference b/w 1/5 and 1/3 is 2/15. Fraction left is 1/15. The no. of bees will be 15 multiply by one which is 15.


However logically, there will be no bees left. All of the bees have left the hive.
Reply:75
Reply:find the common denominator of one fifth and one third first. it's 15.


1/5 = 3/15 (rosebush)


1/3 = 5/15 (honeysuckle)


difference = 5/15 - 3/15 = 2/15


3 X 2/15 = 6/15 (goldenrod)


total so far = 3/15 + 5/15 + 6/15 = 14/15


remaining = 15/15 - 14/15 = 1/15 (daisy)


1/15 = 1


15/15 = 15





There were 15 bees in the hive.